From: Separation of instantaneous mixtures of a particular set of dependent sources using classical ICA methods
Separating
gT=(g 1,g 2,g 3)
κ 4 ( y )
Number of solutions
Solution inR
yes
(±1,0,0)
κ 4 ( a )
2
(0,±1,0)
no
± 1 2 , ± 1 2 , 0
3 κ 4 ( a ) + 2 4
4
(0,0,±1)
-2
0 , ± - 2 κ 4 ( a ) - 2 , ± κ 4 ( a ) κ 4 ( a ) - 2
2 κ 4 ( a ) 2 - κ 4 ( a )
κ 4 ( a ) ≤0
± - 2 κ 4 ( a ) - 2 , 0 , ± κ 4 ( a ) κ 4 ( a ) - 2
± - 4 3 κ 4 ( a ) - 6 , ± - 4 3 κ 4 ( a ) - 6 , ± 3 κ 4 ( a ) + 2 3 κ 4 ( a ) - 6
2 ( 3 κ 4 ( a ) + 2 ) 3 ( 2 - κ 4 ( a ) )
8
κ 4 ( a ) ≤- 2 3